3.2185 \(\int \frac{2+3 x}{(1-2 x)^{5/2} (3+5 x)^2} \, dx\)

Optimal. Leaf size=76 \[ \frac{76}{1331 \sqrt{1-2 x}}-\frac{1}{55 (1-2 x)^{3/2} (5 x+3)}+\frac{76}{1815 (1-2 x)^{3/2}}-\frac{76 \sqrt{\frac{5}{11}} \tanh ^{-1}\left (\sqrt{\frac{5}{11}} \sqrt{1-2 x}\right )}{1331} \]

[Out]

76/(1815*(1 - 2*x)^(3/2)) + 76/(1331*Sqrt[1 - 2*x]) - 1/(55*(1 - 2*x)^(3/2)*(3 + 5*x)) - (76*Sqrt[5/11]*ArcTan
h[Sqrt[5/11]*Sqrt[1 - 2*x]])/1331

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Rubi [A]  time = 0.019041, antiderivative size = 76, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.182, Rules used = {78, 51, 63, 206} \[ \frac{76}{1331 \sqrt{1-2 x}}-\frac{1}{55 (1-2 x)^{3/2} (5 x+3)}+\frac{76}{1815 (1-2 x)^{3/2}}-\frac{76 \sqrt{\frac{5}{11}} \tanh ^{-1}\left (\sqrt{\frac{5}{11}} \sqrt{1-2 x}\right )}{1331} \]

Antiderivative was successfully verified.

[In]

Int[(2 + 3*x)/((1 - 2*x)^(5/2)*(3 + 5*x)^2),x]

[Out]

76/(1815*(1 - 2*x)^(3/2)) + 76/(1331*Sqrt[1 - 2*x]) - 1/(55*(1 - 2*x)^(3/2)*(3 + 5*x)) - (76*Sqrt[5/11]*ArcTan
h[Sqrt[5/11]*Sqrt[1 - 2*x]])/1331

Rule 78

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> -Simp[((b*e - a*f
)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(f*(p + 1)*(c*f - d*e)), x] - Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1)
+ c*f*(p + 1)))/(f*(p + 1)*(c*f - d*e)), Int[(c + d*x)^n*(e + f*x)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e, f,
n}, x] && LtQ[p, -1] && ( !LtQ[n, -1] || IntegerQ[p] ||  !(IntegerQ[n] ||  !(EqQ[e, 0] ||  !(EqQ[c, 0] || LtQ
[p, n]))))

Rule 51

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n + 1
))/((b*c - a*d)*(m + 1)), x] - Dist[(d*(m + n + 2))/((b*c - a*d)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^n,
x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && LtQ[m, -1] &&  !(LtQ[n, -1] && (EqQ[a, 0] || (NeQ[
c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && IntLinearQ[a, b, c, d, m, n, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin{align*} \int \frac{2+3 x}{(1-2 x)^{5/2} (3+5 x)^2} \, dx &=-\frac{1}{55 (1-2 x)^{3/2} (3+5 x)}+\frac{38}{55} \int \frac{1}{(1-2 x)^{5/2} (3+5 x)} \, dx\\ &=\frac{76}{1815 (1-2 x)^{3/2}}-\frac{1}{55 (1-2 x)^{3/2} (3+5 x)}+\frac{38}{121} \int \frac{1}{(1-2 x)^{3/2} (3+5 x)} \, dx\\ &=\frac{76}{1815 (1-2 x)^{3/2}}+\frac{76}{1331 \sqrt{1-2 x}}-\frac{1}{55 (1-2 x)^{3/2} (3+5 x)}+\frac{190 \int \frac{1}{\sqrt{1-2 x} (3+5 x)} \, dx}{1331}\\ &=\frac{76}{1815 (1-2 x)^{3/2}}+\frac{76}{1331 \sqrt{1-2 x}}-\frac{1}{55 (1-2 x)^{3/2} (3+5 x)}-\frac{190 \operatorname{Subst}\left (\int \frac{1}{\frac{11}{2}-\frac{5 x^2}{2}} \, dx,x,\sqrt{1-2 x}\right )}{1331}\\ &=\frac{76}{1815 (1-2 x)^{3/2}}+\frac{76}{1331 \sqrt{1-2 x}}-\frac{1}{55 (1-2 x)^{3/2} (3+5 x)}-\frac{76 \sqrt{\frac{5}{11}} \tanh ^{-1}\left (\sqrt{\frac{5}{11}} \sqrt{1-2 x}\right )}{1331}\\ \end{align*}

Mathematica [C]  time = 0.0115061, size = 46, normalized size = 0.61 \[ -\frac{33-76 (5 x+3) \, _2F_1\left (-\frac{3}{2},1;-\frac{1}{2};-\frac{5}{11} (2 x-1)\right )}{1815 (1-2 x)^{3/2} (5 x+3)} \]

Antiderivative was successfully verified.

[In]

Integrate[(2 + 3*x)/((1 - 2*x)^(5/2)*(3 + 5*x)^2),x]

[Out]

-(33 - 76*(3 + 5*x)*Hypergeometric2F1[-3/2, 1, -1/2, (-5*(-1 + 2*x))/11])/(1815*(1 - 2*x)^(3/2)*(3 + 5*x))

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Maple [A]  time = 0.012, size = 54, normalized size = 0.7 \begin{align*}{\frac{14}{363} \left ( 1-2\,x \right ) ^{-{\frac{3}{2}}}}+{\frac{74}{1331}{\frac{1}{\sqrt{1-2\,x}}}}+{\frac{2}{1331}\sqrt{1-2\,x} \left ( -2\,x-{\frac{6}{5}} \right ) ^{-1}}-{\frac{76\,\sqrt{55}}{14641}{\it Artanh} \left ({\frac{\sqrt{55}}{11}\sqrt{1-2\,x}} \right ) } \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((2+3*x)/(1-2*x)^(5/2)/(3+5*x)^2,x)

[Out]

14/363/(1-2*x)^(3/2)+74/1331/(1-2*x)^(1/2)+2/1331*(1-2*x)^(1/2)/(-2*x-6/5)-76/14641*arctanh(1/11*55^(1/2)*(1-2
*x)^(1/2))*55^(1/2)

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Maxima [A]  time = 2.09552, size = 100, normalized size = 1.32 \begin{align*} \frac{38}{14641} \, \sqrt{55} \log \left (-\frac{\sqrt{55} - 5 \, \sqrt{-2 \, x + 1}}{\sqrt{55} + 5 \, \sqrt{-2 \, x + 1}}\right ) + \frac{2 \,{\left (570 \,{\left (2 \, x - 1\right )}^{2} + 1672 \, x - 1683\right )}}{3993 \,{\left (5 \,{\left (-2 \, x + 1\right )}^{\frac{5}{2}} - 11 \,{\left (-2 \, x + 1\right )}^{\frac{3}{2}}\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)/(1-2*x)^(5/2)/(3+5*x)^2,x, algorithm="maxima")

[Out]

38/14641*sqrt(55)*log(-(sqrt(55) - 5*sqrt(-2*x + 1))/(sqrt(55) + 5*sqrt(-2*x + 1))) + 2/3993*(570*(2*x - 1)^2
+ 1672*x - 1683)/(5*(-2*x + 1)^(5/2) - 11*(-2*x + 1)^(3/2))

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Fricas [A]  time = 1.03041, size = 258, normalized size = 3.39 \begin{align*} \frac{114 \, \sqrt{11} \sqrt{5}{\left (20 \, x^{3} - 8 \, x^{2} - 7 \, x + 3\right )} \log \left (\frac{\sqrt{11} \sqrt{5} \sqrt{-2 \, x + 1} + 5 \, x - 8}{5 \, x + 3}\right ) - 11 \,{\left (2280 \, x^{2} - 608 \, x - 1113\right )} \sqrt{-2 \, x + 1}}{43923 \,{\left (20 \, x^{3} - 8 \, x^{2} - 7 \, x + 3\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)/(1-2*x)^(5/2)/(3+5*x)^2,x, algorithm="fricas")

[Out]

1/43923*(114*sqrt(11)*sqrt(5)*(20*x^3 - 8*x^2 - 7*x + 3)*log((sqrt(11)*sqrt(5)*sqrt(-2*x + 1) + 5*x - 8)/(5*x
+ 3)) - 11*(2280*x^2 - 608*x - 1113)*sqrt(-2*x + 1))/(20*x^3 - 8*x^2 - 7*x + 3)

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Sympy [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)/(1-2*x)**(5/2)/(3+5*x)**2,x)

[Out]

Exception raised: ValueError

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Giac [A]  time = 2.0891, size = 104, normalized size = 1.37 \begin{align*} \frac{38}{14641} \, \sqrt{55} \log \left (\frac{{\left | -2 \, \sqrt{55} + 10 \, \sqrt{-2 \, x + 1} \right |}}{2 \,{\left (\sqrt{55} + 5 \, \sqrt{-2 \, x + 1}\right )}}\right ) + \frac{4 \,{\left (111 \, x - 94\right )}}{3993 \,{\left (2 \, x - 1\right )} \sqrt{-2 \, x + 1}} - \frac{5 \, \sqrt{-2 \, x + 1}}{1331 \,{\left (5 \, x + 3\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)/(1-2*x)^(5/2)/(3+5*x)^2,x, algorithm="giac")

[Out]

38/14641*sqrt(55)*log(1/2*abs(-2*sqrt(55) + 10*sqrt(-2*x + 1))/(sqrt(55) + 5*sqrt(-2*x + 1))) + 4/3993*(111*x
- 94)/((2*x - 1)*sqrt(-2*x + 1)) - 5/1331*sqrt(-2*x + 1)/(5*x + 3)